5(c+2)-3(3c-5)=1

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Solution for 5(c+2)-3(3c-5)=1 equation:


Simplifying
5(c + 2) + -3(3c + -5) = 1

Reorder the terms:
5(2 + c) + -3(3c + -5) = 1
(2 * 5 + c * 5) + -3(3c + -5) = 1
(10 + 5c) + -3(3c + -5) = 1

Reorder the terms:
10 + 5c + -3(-5 + 3c) = 1
10 + 5c + (-5 * -3 + 3c * -3) = 1
10 + 5c + (15 + -9c) = 1

Reorder the terms:
10 + 15 + 5c + -9c = 1

Combine like terms: 10 + 15 = 25
25 + 5c + -9c = 1

Combine like terms: 5c + -9c = -4c
25 + -4c = 1

Solving
25 + -4c = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + -4c = 1 + -25

Combine like terms: 25 + -25 = 0
0 + -4c = 1 + -25
-4c = 1 + -25

Combine like terms: 1 + -25 = -24
-4c = -24

Divide each side by '-4'.
c = 6

Simplifying
c = 6

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