5(c+2)-2(c+1)=17

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Solution for 5(c+2)-2(c+1)=17 equation:


Simplifying
5(c + 2) + -2(c + 1) = 17

Reorder the terms:
5(2 + c) + -2(c + 1) = 17
(2 * 5 + c * 5) + -2(c + 1) = 17
(10 + 5c) + -2(c + 1) = 17

Reorder the terms:
10 + 5c + -2(1 + c) = 17
10 + 5c + (1 * -2 + c * -2) = 17
10 + 5c + (-2 + -2c) = 17

Reorder the terms:
10 + -2 + 5c + -2c = 17

Combine like terms: 10 + -2 = 8
8 + 5c + -2c = 17

Combine like terms: 5c + -2c = 3c
8 + 3c = 17

Solving
8 + 3c = 17

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 3c = 17 + -8

Combine like terms: 8 + -8 = 0
0 + 3c = 17 + -8
3c = 17 + -8

Combine like terms: 17 + -8 = 9
3c = 9

Divide each side by '3'.
c = 3

Simplifying
c = 3

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