5(c+1)=3(c-5)

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Solution for 5(c+1)=3(c-5) equation: 



5(c+1)=3(c-5)

We move all terms to the left:

5(c+1)-(3(c-5))=0

We multiply parentheses

5c-(3(c-5))+5=0



We calculate terms in parentheses: -(3(c-5)), so:

3(c-5)

We multiply parentheses

3c-15

Back to the equation:

-(3c-15)



We get rid of parentheses

5c-3c+15+5=0

We add all the numbers together, and all the variables

2c+20=0

We move all terms containing c to the left, all other terms to the right

2c=-20

c=-20/2

c=-10

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