5(b-4)=4(b-3)

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Solution for 5(b-4)=4(b-3) equation:


Simplifying
5(b + -4) = 4(b + -3)

Reorder the terms:
5(-4 + b) = 4(b + -3)
(-4 * 5 + b * 5) = 4(b + -3)
(-20 + 5b) = 4(b + -3)

Reorder the terms:
-20 + 5b = 4(-3 + b)
-20 + 5b = (-3 * 4 + b * 4)
-20 + 5b = (-12 + 4b)

Solving
-20 + 5b = -12 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-20 + 5b + -4b = -12 + 4b + -4b

Combine like terms: 5b + -4b = 1b
-20 + 1b = -12 + 4b + -4b

Combine like terms: 4b + -4b = 0
-20 + 1b = -12 + 0
-20 + 1b = -12

Add '20' to each side of the equation.
-20 + 20 + 1b = -12 + 20

Combine like terms: -20 + 20 = 0
0 + 1b = -12 + 20
1b = -12 + 20

Combine like terms: -12 + 20 = 8
1b = 8

Divide each side by '1'.
b = 8

Simplifying
b = 8

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