5(b-4)-6b=4(b-5)

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Solution for 5(b-4)-6b=4(b-5) equation:



5(b-4)-6b=4(b-5)
We move all terms to the left:
5(b-4)-6b-(4(b-5))=0
We add all the numbers together, and all the variables
-6b+5(b-4)-(4(b-5))=0
We multiply parentheses
-6b+5b-(4(b-5))-20=0
We calculate terms in parentheses: -(4(b-5)), so:
4(b-5)
We multiply parentheses
4b-20
Back to the equation:
-(4b-20)
We add all the numbers together, and all the variables
-1b-(4b-20)-20=0
We get rid of parentheses
-1b-4b+20-20=0
We add all the numbers together, and all the variables
-5b=0
b=0/-5
b=0

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