5(b-4)+2b=3(b+4)

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Solution for 5(b-4)+2b=3(b+4) equation:


Simplifying
5(b + -4) + 2b = 3(b + 4)

Reorder the terms:
5(-4 + b) + 2b = 3(b + 4)
(-4 * 5 + b * 5) + 2b = 3(b + 4)
(-20 + 5b) + 2b = 3(b + 4)

Combine like terms: 5b + 2b = 7b
-20 + 7b = 3(b + 4)

Reorder the terms:
-20 + 7b = 3(4 + b)
-20 + 7b = (4 * 3 + b * 3)
-20 + 7b = (12 + 3b)

Solving
-20 + 7b = 12 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-20 + 7b + -3b = 12 + 3b + -3b

Combine like terms: 7b + -3b = 4b
-20 + 4b = 12 + 3b + -3b

Combine like terms: 3b + -3b = 0
-20 + 4b = 12 + 0
-20 + 4b = 12

Add '20' to each side of the equation.
-20 + 20 + 4b = 12 + 20

Combine like terms: -20 + 20 = 0
0 + 4b = 12 + 20
4b = 12 + 20

Combine like terms: 12 + 20 = 32
4b = 32

Divide each side by '4'.
b = 8

Simplifying
b = 8

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