5(b-3)=4(b+1)

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Solution for 5(b-3)=4(b+1) equation:


Simplifying
5(b + -3) = 4(b + 1)

Reorder the terms:
5(-3 + b) = 4(b + 1)
(-3 * 5 + b * 5) = 4(b + 1)
(-15 + 5b) = 4(b + 1)

Reorder the terms:
-15 + 5b = 4(1 + b)
-15 + 5b = (1 * 4 + b * 4)
-15 + 5b = (4 + 4b)

Solving
-15 + 5b = 4 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-15 + 5b + -4b = 4 + 4b + -4b

Combine like terms: 5b + -4b = 1b
-15 + 1b = 4 + 4b + -4b

Combine like terms: 4b + -4b = 0
-15 + 1b = 4 + 0
-15 + 1b = 4

Add '15' to each side of the equation.
-15 + 15 + 1b = 4 + 15

Combine like terms: -15 + 15 = 0
0 + 1b = 4 + 15
1b = 4 + 15

Combine like terms: 4 + 15 = 19
1b = 19

Divide each side by '1'.
b = 19

Simplifying
b = 19

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