5(b-3)+12=-2(b-2)

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Solution for 5(b-3)+12=-2(b-2) equation:


Simplifying
5(b + -3) + 12 = -2(b + -2)

Reorder the terms:
5(-3 + b) + 12 = -2(b + -2)
(-3 * 5 + b * 5) + 12 = -2(b + -2)
(-15 + 5b) + 12 = -2(b + -2)

Reorder the terms:
-15 + 12 + 5b = -2(b + -2)

Combine like terms: -15 + 12 = -3
-3 + 5b = -2(b + -2)

Reorder the terms:
-3 + 5b = -2(-2 + b)
-3 + 5b = (-2 * -2 + b * -2)
-3 + 5b = (4 + -2b)

Solving
-3 + 5b = 4 + -2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2b' to each side of the equation.
-3 + 5b + 2b = 4 + -2b + 2b

Combine like terms: 5b + 2b = 7b
-3 + 7b = 4 + -2b + 2b

Combine like terms: -2b + 2b = 0
-3 + 7b = 4 + 0
-3 + 7b = 4

Add '3' to each side of the equation.
-3 + 3 + 7b = 4 + 3

Combine like terms: -3 + 3 = 0
0 + 7b = 4 + 3
7b = 4 + 3

Combine like terms: 4 + 3 = 7
7b = 7

Divide each side by '7'.
b = 1

Simplifying
b = 1

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