5(b-2)=4(b-1)

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Solution for 5(b-2)=4(b-1) equation:


Simplifying
5(b + -2) = 4(b + -1)

Reorder the terms:
5(-2 + b) = 4(b + -1)
(-2 * 5 + b * 5) = 4(b + -1)
(-10 + 5b) = 4(b + -1)

Reorder the terms:
-10 + 5b = 4(-1 + b)
-10 + 5b = (-1 * 4 + b * 4)
-10 + 5b = (-4 + 4b)

Solving
-10 + 5b = -4 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-10 + 5b + -4b = -4 + 4b + -4b

Combine like terms: 5b + -4b = 1b
-10 + 1b = -4 + 4b + -4b

Combine like terms: 4b + -4b = 0
-10 + 1b = -4 + 0
-10 + 1b = -4

Add '10' to each side of the equation.
-10 + 10 + 1b = -4 + 10

Combine like terms: -10 + 10 = 0
0 + 1b = -4 + 10
1b = -4 + 10

Combine like terms: -4 + 10 = 6
1b = 6

Divide each side by '1'.
b = 6

Simplifying
b = 6

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