5(b-12)=4b-48

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Solution for 5(b-12)=4b-48 equation: 



5(b-12)=4b-48

We move all terms to the left:

5(b-12)-(4b-48)=0

We multiply parentheses

5b-(4b-48)-60=0

We get rid of parentheses

5b-4b+48-60=0

We add all the numbers together, and all the variables

b-12=0

We move all terms containing b to the left, all other terms to the right

b=12

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