5(b+4)=2+2(b+3)

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Solution for 5(b+4)=2+2(b+3) equation: 



5(b+4)=2+2(b+3)

We move all terms to the left:

5(b+4)-(2+2(b+3))=0

We multiply parentheses

5b-(2+2(b+3))+20=0



We calculate terms in parentheses: -(2+2(b+3)), so:

2+2(b+3)

determiningTheFunctionDomain
2(b+3)+2

We multiply parentheses

2b+6+2

We add all the numbers together, and all the variables

2b+8

Back to the equation:

-(2b+8)



We get rid of parentheses

5b-2b-8+20=0

We add all the numbers together, and all the variables

3b+12=0

We move all terms containing b to the left, all other terms to the right

3b=-12

b=-12/3

b=-4

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