5(b+3)=2(3b-18)

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Solution for 5(b+3)=2(3b-18) equation: 



5(b+3)=2(3b-18)

We move all terms to the left:

5(b+3)-(2(3b-18))=0

We multiply parentheses

5b-(2(3b-18))+15=0



We calculate terms in parentheses: -(2(3b-18)), so:

2(3b-18)

We multiply parentheses

6b-36

Back to the equation:

-(6b-36)



We get rid of parentheses

5b-6b+36+15=0

We add all the numbers together, and all the variables

-1b+51=0

We move all terms containing b to the left, all other terms to the right

-b=-51

b=-51/-1

b=+51

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