5(b+3)+6b=92

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Solution for 5(b+3)+6b=92 equation: 



5(b+3)+6b=92

We move all terms to the left:

5(b+3)+6b-(92)=0

We add all the numbers together, and all the variables

6b+5(b+3)-92=0

We multiply parentheses

6b+5b+15-92=0

We add all the numbers together, and all the variables

11b-77=0

We move all terms containing b to the left, all other terms to the right

11b=77

b=77/11

b=7

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