5(b+2)=3(b+3)

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Solution for 5(b+2)=3(b+3) equation: 



5(b+2)=3(b+3)

We move all terms to the left:

5(b+2)-(3(b+3))=0

We multiply parentheses

5b-(3(b+3))+10=0



We calculate terms in parentheses: -(3(b+3)), so:

3(b+3)

We multiply parentheses

3b+9

Back to the equation:

-(3b+9)



We get rid of parentheses

5b-3b-9+10=0

We add all the numbers together, and all the variables

2b+1=0

We move all terms containing b to the left, all other terms to the right

2b=-1

b=-1/2

b=-1/2

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