5(b+2)=-(-3b-12)

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Solution for 5(b+2)=-(-3b-12) equation:


Simplifying
5(b + 2) = -1(-3b + -12)

Reorder the terms:
5(2 + b) = -1(-3b + -12)
(2 * 5 + b * 5) = -1(-3b + -12)
(10 + 5b) = -1(-3b + -12)

Reorder the terms:
10 + 5b = -1(-12 + -3b)
10 + 5b = (-12 * -1 + -3b * -1)
10 + 5b = (12 + 3b)

Solving
10 + 5b = 12 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
10 + 5b + -3b = 12 + 3b + -3b

Combine like terms: 5b + -3b = 2b
10 + 2b = 12 + 3b + -3b

Combine like terms: 3b + -3b = 0
10 + 2b = 12 + 0
10 + 2b = 12

Add '-10' to each side of the equation.
10 + -10 + 2b = 12 + -10

Combine like terms: 10 + -10 = 0
0 + 2b = 12 + -10
2b = 12 + -10

Combine like terms: 12 + -10 = 2
2b = 2

Divide each side by '2'.
b = 1

Simplifying
b = 1

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