5(b+1)=3(b+3)=

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Solution for 5(b+1)=3(b+3)= equation: 



5(b+1)=3(b+3)=

We move all terms to the left:

5(b+1)-(3(b+3))=0

We multiply parentheses

5b-(3(b+3))+5=0



We calculate terms in parentheses: -(3(b+3)), so:

3(b+3)

We multiply parentheses

3b+9

Back to the equation:

-(3b+9)



We get rid of parentheses

5b-3b-9+5=0

We add all the numbers together, and all the variables

2b-4=0

We move all terms containing b to the left, all other terms to the right

2b=4

b=4/2

b=2

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