5(b+1)2+20=155

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Solution for 5(b+1)2+20=155 equation: 



5(b+1)2+20=155

We move all terms to the left:

5(b+1)2+20-(155)=0

We add all the numbers together, and all the variables

5(b+1)2-135=0

We multiply parentheses

10b+10-135=0

We add all the numbers together, and all the variables

10b-125=0

We move all terms containing b to the left, all other terms to the right

10b=125

b=125/10

b=12+1/2

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