5(a-5)+11=2(a-4)

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Solution for 5(a-5)+11=2(a-4) equation:


Simplifying
5(a + -5) + 11 = 2(a + -4)

Reorder the terms:
5(-5 + a) + 11 = 2(a + -4)
(-5 * 5 + a * 5) + 11 = 2(a + -4)
(-25 + 5a) + 11 = 2(a + -4)

Reorder the terms:
-25 + 11 + 5a = 2(a + -4)

Combine like terms: -25 + 11 = -14
-14 + 5a = 2(a + -4)

Reorder the terms:
-14 + 5a = 2(-4 + a)
-14 + 5a = (-4 * 2 + a * 2)
-14 + 5a = (-8 + 2a)

Solving
-14 + 5a = -8 + 2a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2a' to each side of the equation.
-14 + 5a + -2a = -8 + 2a + -2a

Combine like terms: 5a + -2a = 3a
-14 + 3a = -8 + 2a + -2a

Combine like terms: 2a + -2a = 0
-14 + 3a = -8 + 0
-14 + 3a = -8

Add '14' to each side of the equation.
-14 + 14 + 3a = -8 + 14

Combine like terms: -14 + 14 = 0
0 + 3a = -8 + 14
3a = -8 + 14

Combine like terms: -8 + 14 = 6
3a = 6

Divide each side by '3'.
a = 2

Simplifying
a = 2

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