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5(a-1)-3(2-a)=3(2a-4+2(25-5a)
We move all terms to the left:
5(a-1)-3(2-a)-(3(2a-4+2(25-5a))=0
We add all the numbers together, and all the variables
5(a-1)-3(-1a+2)-(3(2a-4+2(-5a+25))=0
We multiply parentheses
5a+3a-(3(2a-4+2(-5a+25))-5-6=0
We add all the numbers together, and all the variables
8a-(3(2a-4+2(-5a+25))-5-6=0
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