5(a+4)=4(a+5)-3

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Solution for 5(a+4)=4(a+5)-3 equation: 



5(a+4)=4(a+5)-3

We move all terms to the left:

5(a+4)-(4(a+5)-3)=0

We multiply parentheses

5a-(4(a+5)-3)+20=0



We calculate terms in parentheses: -(4(a+5)-3), so:

4(a+5)-3

We multiply parentheses

4a+20-3

We add all the numbers together, and all the variables

4a+17

Back to the equation:

-(4a+17)



We get rid of parentheses

5a-4a-17+20=0

We add all the numbers together, and all the variables

a+3=0

We move all terms containing a to the left, all other terms to the right

a=-3

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