5(a+2)=4(4a-1)

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Solution for 5(a+2)=4(4a-1) equation: 



5(a+2)=4(4a-1)

We move all terms to the left:

5(a+2)-(4(4a-1))=0

We multiply parentheses

5a-(4(4a-1))+10=0



We calculate terms in parentheses: -(4(4a-1)), so:

4(4a-1)

We multiply parentheses

16a-4

Back to the equation:

-(16a-4)



We get rid of parentheses

5a-16a+4+10=0

We add all the numbers together, and all the variables

-11a+14=0

We move all terms containing a to the left, all other terms to the right

-11a=-14

a=-14/-11

a=1+3/11

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