5(X+2)=47+3(x+4)

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Solution for 5(X+2)=47+3(x+4) equation: 



5(X+2)=47+3(X+4)

We move all terms to the left:

5(X+2)-(47+3(X+4))=0

We multiply parentheses

5X-(47+3(X+4))+10=0



We calculate terms in parentheses: -(47+3(X+4)), so:

47+3(X+4)

determiningTheFunctionDomain
3(X+4)+47

We multiply parentheses

3X+12+47

We add all the numbers together, and all the variables

3X+59

Back to the equation:

-(3X+59)



We get rid of parentheses

5X-3X-59+10=0

We add all the numbers together, and all the variables

2X-49=0

We move all terms containing X to the left, all other terms to the right

2X=49

X=49/2

X=24+1/2

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