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5(9x-31)(12x-44)=1120
We move all terms to the left:
5(9x-31)(12x-44)-(1120)=0
We multiply parentheses ..
5(+108x^2-396x-372x+1364)-1120=0
We multiply parentheses
540x^2-1980x-1860x+6820-1120=0
We add all the numbers together, and all the variables
540x^2-3840x+5700=0
a = 540; b = -3840; c = +5700;
Δ = b2-4ac
Δ = -38402-4·540·5700
Δ = 2433600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2433600}=1560$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3840)-1560}{2*540}=\frac{2280}{1080} =2+1/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3840)+1560}{2*540}=\frac{5400}{1080} =5 $
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