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5(9+2)-3(3a-5)=1
We move all terms to the left:
5(9+2)-3(3a-5)-(1)=0
determiningTheFunctionDomain -3(3a-5)-1+5(9+2)=0
We add all the numbers together, and all the variables
-3(3a-5)-1+511=0
We add all the numbers together, and all the variables
-3(3a-5)+510=0
We multiply parentheses
-9a+15+510=0
We add all the numbers together, and all the variables
-9a+525=0
We move all terms containing a to the left, all other terms to the right
-9a=-525
a=-525/-9
a=58+1/3
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