5(8y-)=-(y-4)

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Solution for 5(8y-)=-(y-4) equation: 



5(8y-)=-(y-4)

We move all terms to the left:

5(8y-)-(-(y-4))=0

We add all the numbers together, and all the variables

5(+8y)-(-(y-4))=0

We multiply parentheses

40y-(-(y-4))=0



We calculate terms in parentheses: -(-(y-4)), so:

-(y-4)

We get rid of parentheses

-y+4

We add all the numbers together, and all the variables

-1y+4

Back to the equation:

-(-1y+4)



We get rid of parentheses

40y+1y-4=0

We add all the numbers together, and all the variables

41y-4=0

We move all terms containing y to the left, all other terms to the right

41y=4

y=4/41

y=4/41

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