5(8x+4)-7(x+1)=

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Solution for 5(8x+4)-7(x+1)= equation:


5(8x+4)-7(x+1)=0

We simplify the equation to the form, which is simple to understand
5(8x+4)-7(x+1)=0

Reorder the terms in parentheses
+(+40x+20)-7*(x+1)=0

Remove unnecessary parentheses
+40x+20-7+*(+x+1+)=0

Reorder the terms in parentheses
+40x+20+(-7x-7)=0

Remove unnecessary parentheses
+40x+20-7x-7=0

We move all terms containing x to the left and all other terms to the right.
+40x-7x=0-20+7

We simplify left and right side of the equation.
+33x=-13

We divide both sides of the equation by 33 to get x.
x=-0.393939393939

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