5(7b-6)+2=2(17b+4)-6

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Solution for 5(7b-6)+2=2(17b+4)-6 equation: 



5(7b-6)+2=2(17b+4)-6

We move all terms to the left:

5(7b-6)+2-(2(17b+4)-6)=0

We multiply parentheses

35b-(2(17b+4)-6)-30+2=0



We calculate terms in parentheses: -(2(17b+4)-6), so:

2(17b+4)-6

We multiply parentheses

34b+8-6

We add all the numbers together, and all the variables

34b+2

Back to the equation:

-(34b+2)



We add all the numbers together, and all the variables

35b-(34b+2)-28=0

We get rid of parentheses

35b-34b-2-28=0

We add all the numbers together, and all the variables

b-30=0

We move all terms containing b to the left, all other terms to the right

b=30

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