5(7-a)-3(a-4)=4(3-2a)+7

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Solution for 5(7-a)-3(a-4)=4(3-2a)+7 equation: 



5(7-a)-3(a-4)=4(3-2a)+7

We move all terms to the left:

5(7-a)-3(a-4)-(4(3-2a)+7)=0

We add all the numbers together, and all the variables

5(-1a+7)-3(a-4)-(4(-2a+3)+7)=0

We multiply parentheses

-5a-3a-(4(-2a+3)+7)+35+12=0



We calculate terms in parentheses: -(4(-2a+3)+7), so:

4(-2a+3)+7

We multiply parentheses

-8a+12+7

We add all the numbers together, and all the variables

-8a+19

Back to the equation:

-(-8a+19)



We add all the numbers together, and all the variables

-8a-(-8a+19)+47=0

We get rid of parentheses

-8a+8a-19+47=0

We add all the numbers together, and all the variables

28!=0

There is no solution for this equation

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