5(6z-1)-4(2+4)=10(z+1)

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Solution for 5(6z-1)-4(2+4)=10(z+1) equation:


Simplifying
5(6z + -1) + -4(2 + 4) = 10(z + 1)

Reorder the terms:
5(-1 + 6z) + -4(2 + 4) = 10(z + 1)
(-1 * 5 + 6z * 5) + -4(2 + 4) = 10(z + 1)
(-5 + 30z) + -4(2 + 4) = 10(z + 1)

Combine like terms: 2 + 4 = 6
-5 + 30z + -4(6) = 10(z + 1)

Multiply -4 * 6
-5 + 30z + -24 = 10(z + 1)

Reorder the terms:
-5 + -24 + 30z = 10(z + 1)

Combine like terms: -5 + -24 = -29
-29 + 30z = 10(z + 1)

Reorder the terms:
-29 + 30z = 10(1 + z)
-29 + 30z = (1 * 10 + z * 10)
-29 + 30z = (10 + 10z)

Solving
-29 + 30z = 10 + 10z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-10z' to each side of the equation.
-29 + 30z + -10z = 10 + 10z + -10z

Combine like terms: 30z + -10z = 20z
-29 + 20z = 10 + 10z + -10z

Combine like terms: 10z + -10z = 0
-29 + 20z = 10 + 0
-29 + 20z = 10

Add '29' to each side of the equation.
-29 + 29 + 20z = 10 + 29

Combine like terms: -29 + 29 = 0
0 + 20z = 10 + 29
20z = 10 + 29

Combine like terms: 10 + 29 = 39
20z = 39

Divide each side by '20'.
z = 1.95

Simplifying
z = 1.95

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