5(6y-1)+19=-1-(3y+2)

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Solution for 5(6y-1)+19=-1-(3y+2) equation: 



5(6y-1)+19=-1-(3y+2)

We move all terms to the left:

5(6y-1)+19-(-1-(3y+2))=0

We multiply parentheses

30y-(-1-(3y+2))-5+19=0



We calculate terms in parentheses: -(-1-(3y+2)), so:

-1-(3y+2)

determiningTheFunctionDomain
-(3y+2)-1

We get rid of parentheses

-3y-2-1

We add all the numbers together, and all the variables

-3y-3

Back to the equation:

-(-3y-3)



We add all the numbers together, and all the variables

30y-(-3y-3)+14=0

We get rid of parentheses

30y+3y+3+14=0

We add all the numbers together, and all the variables

33y+17=0

We move all terms containing y to the left, all other terms to the right

33y=-17

y=-17/33

y=-17/33

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