5(6y+3)-15=4(2y+2)+21

Solution for 5(6y+3)-15=4(2y+2)+21 equation:

5(6y+3)-15=4(2y+2)+21

We move all terms to the left:

5(6y+3)-15-(4(2y+2)+21)=0

We multiply parentheses

30y-(4(2y+2)+21)+15-15=0


We calculate terms in parentheses: -(4(2y+2)+21), so:

4(2y+2)+21

We multiply parentheses

8y+8+21

We add all the numbers together, and all the variables

8y+29

Back to the equation:

-(8y+29)


We add all the numbers together, and all the variables

30y-(8y+29)=0

We get rid of parentheses

30y-8y-29=0

We add all the numbers together, and all the variables

22y-29=0

We move all terms containing y to the left, all other terms to the right

22y=29

y=29/22

y=1+7/22