5(6x-8)-10=4(3x+2)+6x

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Solution for 5(6x-8)-10=4(3x+2)+6x equation: 



5(6x-8)-10=4(3x+2)+6x

We move all terms to the left:

5(6x-8)-10-(4(3x+2)+6x)=0

We multiply parentheses

30x-(4(3x+2)+6x)-40-10=0



We calculate terms in parentheses: -(4(3x+2)+6x), so:

4(3x+2)+6x

We add all the numbers together, and all the variables

6x+4(3x+2)

We multiply parentheses

6x+12x+8

We add all the numbers together, and all the variables

18x+8

Back to the equation:

-(18x+8)



We add all the numbers together, and all the variables

30x-(18x+8)-50=0

We get rid of parentheses

30x-18x-8-50=0

We add all the numbers together, and all the variables

12x-58=0

We move all terms containing x to the left, all other terms to the right

12x=58

x=58/12

x=4+5/6

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