5(6b+5)=b-33

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Solution for 5(6b+5)=b-33 equation: 



5(6b+5)=b-33

We move all terms to the left:

5(6b+5)-(b-33)=0

We multiply parentheses

30b-(b-33)+25=0

We get rid of parentheses

30b-b+33+25=0

We add all the numbers together, and all the variables

29b+58=0

We move all terms containing b to the left, all other terms to the right

29b=-58

b=-58/29

b=-2

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