5(6a+1)=7(4a+3)

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Solution for 5(6a+1)=7(4a+3) equation: 



5(6a+1)=7(4a+3)

We move all terms to the left:

5(6a+1)-(7(4a+3))=0

We multiply parentheses

30a-(7(4a+3))+5=0



We calculate terms in parentheses: -(7(4a+3)), so:

7(4a+3)

We multiply parentheses

28a+21

Back to the equation:

-(28a+21)



We get rid of parentheses

30a-28a-21+5=0

We add all the numbers together, and all the variables

2a-16=0

We move all terms containing a to the left, all other terms to the right

2a=16

a=16/2

a=8

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