5(6-2t)=2(t+6)

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Solution for 5(6-2t)=2(t+6) equation:



5(6-2t)=2(t+6)
We move all terms to the left:
5(6-2t)-(2(t+6))=0
We add all the numbers together, and all the variables
5(-2t+6)-(2(t+6))=0
We multiply parentheses
-10t-(2(t+6))+30=0
We calculate terms in parentheses: -(2(t+6)), so:
2(t+6)
We multiply parentheses
2t+12
Back to the equation:
-(2t+12)
We get rid of parentheses
-10t-2t-12+30=0
We add all the numbers together, and all the variables
-12t+18=0
We move all terms containing t to the left, all other terms to the right
-12t=-18
t=-18/-12
t=1+1/2

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