5(6+c)=4(4+c)

Solution for 5(6+c)=4(4+c) equation:

5(6+c)=4(4+c)

We move all terms to the left:

5(6+c)-(4(4+c))=0

We add all the numbers together, and all the variables

5(c+6)-(4(c+4))=0

We multiply parentheses

5c-(4(c+4))+30=0


We calculate terms in parentheses: -(4(c+4)), so:

4(c+4)

We multiply parentheses

4c+16

Back to the equation:

-(4c+16)


We get rid of parentheses

5c-4c-16+30=0

We add all the numbers together, and all the variables

c+14=0

We move all terms containing c to the left, all other terms to the right

c=-14