5(5x+3)+5(2x+4)+6=35x+41

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Solution for 5(5x+3)+5(2x+4)+6=35x+41 equation:


Simplifying
5(5x + 3) + 5(2x + 4) + 6 = 35x + 41

Reorder the terms:
5(3 + 5x) + 5(2x + 4) + 6 = 35x + 41
(3 * 5 + 5x * 5) + 5(2x + 4) + 6 = 35x + 41
(15 + 25x) + 5(2x + 4) + 6 = 35x + 41

Reorder the terms:
15 + 25x + 5(4 + 2x) + 6 = 35x + 41
15 + 25x + (4 * 5 + 2x * 5) + 6 = 35x + 41
15 + 25x + (20 + 10x) + 6 = 35x + 41

Reorder the terms:
15 + 20 + 6 + 25x + 10x = 35x + 41

Combine like terms: 15 + 20 = 35
35 + 6 + 25x + 10x = 35x + 41

Combine like terms: 35 + 6 = 41
41 + 25x + 10x = 35x + 41

Combine like terms: 25x + 10x = 35x
41 + 35x = 35x + 41

Reorder the terms:
41 + 35x = 41 + 35x

Add '-41' to each side of the equation.
41 + -41 + 35x = 41 + -41 + 35x

Combine like terms: 41 + -41 = 0
0 + 35x = 41 + -41 + 35x
35x = 41 + -41 + 35x

Combine like terms: 41 + -41 = 0
35x = 0 + 35x
35x = 35x

Add '-35x' to each side of the equation.
35x + -35x = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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