5(5v-3)(2v-3)=0

Solution for 5(5v-3)(2v-3)=0 equation:

5(5v-3)(2v-3)=0

We multiply parentheses ..

5(+10v^2-15v-6v+9)=0

We multiply parentheses

50v^2-75v-30v+45=0

We add all the numbers together, and all the variables

50v^2-105v+45=0

a = 50; b = -105; c = +45;
Δ = b2-4ac
Δ = -1052-4·50·45
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-45}{2*50}=\frac{60}{100}
=3/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+45}{2*50}=\frac{150}{100}
=1+1/2
$