5(5+c)=4(c-3)=

Solution for 5(5+c)=4(c-3)= equation:

5(5+c)=4(c-3)=

We move all terms to the left:

5(5+c)-(4(c-3))=0

We add all the numbers together, and all the variables

5(c+5)-(4(c-3))=0

We multiply parentheses

5c-(4(c-3))+25=0


We calculate terms in parentheses: -(4(c-3)), so:

4(c-3)

We multiply parentheses

4c-12

Back to the equation:

-(4c-12)


We get rid of parentheses

5c-4c+12+25=0

We add all the numbers together, and all the variables

c+37=0

We move all terms containing c to the left, all other terms to the right

c=-37