5(4z-1)-2(z+4)=8(z+1)

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Solution for 5(4z-1)-2(z+4)=8(z+1) equation:


Simplifying
5(4z + -1) + -2(z + 4) = 8(z + 1)

Reorder the terms:
5(-1 + 4z) + -2(z + 4) = 8(z + 1)
(-1 * 5 + 4z * 5) + -2(z + 4) = 8(z + 1)
(-5 + 20z) + -2(z + 4) = 8(z + 1)

Reorder the terms:
-5 + 20z + -2(4 + z) = 8(z + 1)
-5 + 20z + (4 * -2 + z * -2) = 8(z + 1)
-5 + 20z + (-8 + -2z) = 8(z + 1)

Reorder the terms:
-5 + -8 + 20z + -2z = 8(z + 1)

Combine like terms: -5 + -8 = -13
-13 + 20z + -2z = 8(z + 1)

Combine like terms: 20z + -2z = 18z
-13 + 18z = 8(z + 1)

Reorder the terms:
-13 + 18z = 8(1 + z)
-13 + 18z = (1 * 8 + z * 8)
-13 + 18z = (8 + 8z)

Solving
-13 + 18z = 8 + 8z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-8z' to each side of the equation.
-13 + 18z + -8z = 8 + 8z + -8z

Combine like terms: 18z + -8z = 10z
-13 + 10z = 8 + 8z + -8z

Combine like terms: 8z + -8z = 0
-13 + 10z = 8 + 0
-13 + 10z = 8

Add '13' to each side of the equation.
-13 + 13 + 10z = 8 + 13

Combine like terms: -13 + 13 = 0
0 + 10z = 8 + 13
10z = 8 + 13

Combine like terms: 8 + 13 = 21
10z = 21

Divide each side by '10'.
z = 2.1

Simplifying
z = 2.1

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