5(4y-4)=5(3y+3)

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Solution for 5(4y-4)=5(3y+3) equation: 



5(4y-4)=5(3y+3)

We move all terms to the left:

5(4y-4)-(5(3y+3))=0

We multiply parentheses

20y-(5(3y+3))-20=0



We calculate terms in parentheses: -(5(3y+3)), so:

5(3y+3)

We multiply parentheses

15y+15

Back to the equation:

-(15y+15)



We get rid of parentheses

20y-15y-15-20=0

We add all the numbers together, and all the variables

5y-35=0

We move all terms containing y to the left, all other terms to the right

5y=35

y=35/5

y=7

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