5(4x-9)-5=5(x-4)+45

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Solution for 5(4x-9)-5=5(x-4)+45 equation: 



5(4x-9)-5=5(x-4)+45

We move all terms to the left:

5(4x-9)-5-(5(x-4)+45)=0

We multiply parentheses

20x-(5(x-4)+45)-45-5=0



We calculate terms in parentheses: -(5(x-4)+45), so:

5(x-4)+45

We multiply parentheses

5x-20+45

We add all the numbers together, and all the variables

5x+25

Back to the equation:

-(5x+25)



We add all the numbers together, and all the variables

20x-(5x+25)-50=0

We get rid of parentheses

20x-5x-25-50=0

We add all the numbers together, and all the variables

15x-75=0

We move all terms containing x to the left, all other terms to the right

15x=75

x=75/15

x=5

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