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5(4x-7)(7x+2)=0
We multiply parentheses ..
5(+28x^2+8x-49x-14)=0
We multiply parentheses
140x^2+40x-245x-70=0
We add all the numbers together, and all the variables
140x^2-205x-70=0
a = 140; b = -205; c = -70;
Δ = b2-4ac
Δ = -2052-4·140·(-70)
Δ = 81225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81225}=285$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-205)-285}{2*140}=\frac{-80}{280} =-2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-205)+285}{2*140}=\frac{490}{280} =1+3/4 $
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