5(4x-4)=4x+28

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Solution for 5(4x-4)=4x+28 equation: 



5(4x-4)=4x+28

We move all terms to the left:

5(4x-4)-(4x+28)=0

We multiply parentheses

20x-(4x+28)-20=0

We get rid of parentheses

20x-4x-28-20=0

We add all the numbers together, and all the variables

16x-48=0

We move all terms containing x to the left, all other terms to the right

16x=48

x=48/16

x=3

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