5(4x-3)=3(-4x+4)+101

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Solution for 5(4x-3)=3(-4x+4)+101 equation: 



5(4x-3)=3(-4x+4)+101

We move all terms to the left:

5(4x-3)-(3(-4x+4)+101)=0

We multiply parentheses

20x-(3(-4x+4)+101)-15=0



We calculate terms in parentheses: -(3(-4x+4)+101), so:

3(-4x+4)+101

We multiply parentheses

-12x+12+101

We add all the numbers together, and all the variables

-12x+113

Back to the equation:

-(-12x+113)



We get rid of parentheses

20x+12x-113-15=0

We add all the numbers together, and all the variables

32x-128=0

We move all terms containing x to the left, all other terms to the right

32x=128

x=128/32

x=4

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