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5(4x-3)-5x=10-2(3x-1)
We move all terms to the left:
5(4x-3)-5x-(10-2(3x-1))=0
We add all the numbers together, and all the variables
-5x+5(4x-3)-(10-2(3x-1))=0
We multiply parentheses
-5x+20x-(10-2(3x-1))-15=0
We calculate terms in parentheses: -(10-2(3x-1)), so:We add all the numbers together, and all the variables
10-2(3x-1)
determiningTheFunctionDomain -2(3x-1)+10
We multiply parentheses
-6x+2+10
We add all the numbers together, and all the variables
-6x+12
Back to the equation:
-(-6x+12)
15x-(-6x+12)-15=0
We get rid of parentheses
15x+6x-12-15=0
We add all the numbers together, and all the variables
21x-27=0
We move all terms containing x to the left, all other terms to the right
21x=27
x=27/21
x=1+2/7
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