5(4x-3)+10x=3(x+4)

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Solution for 5(4x-3)+10x=3(x+4) equation: 



5(4x-3)+10x=3(x+4)

We move all terms to the left:

5(4x-3)+10x-(3(x+4))=0

We add all the numbers together, and all the variables

10x+5(4x-3)-(3(x+4))=0

We multiply parentheses

10x+20x-(3(x+4))-15=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

30x-(3x+12)-15=0

We get rid of parentheses

30x-3x-12-15=0

We add all the numbers together, and all the variables

27x-27=0

We move all terms containing x to the left, all other terms to the right

27x=27

x=27/27

x=1

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