5(4x-10)=8(2x)-70

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Solution for 5(4x-10)=8(2x)-70 equation: 



5(4x-10)=8(2x)-70

We move all terms to the left:

5(4x-10)-(8(2x)-70)=0

We multiply parentheses

20x-(82x-70)-50=0

We get rid of parentheses

20x-82x+70-50=0

We add all the numbers together, and all the variables

-62x+20=0

We move all terms containing x to the left, all other terms to the right

-62x=-20

x=-20/-62

x=10/31

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