5(4x-10)+10=4(2x-3)+2(x-4)

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Solution for 5(4x-10)+10=4(2x-3)+2(x-4) equation: 



5(4x-10)+10=4(2x-3)+2(x-4)

We move all terms to the left:

5(4x-10)+10-(4(2x-3)+2(x-4))=0

We multiply parentheses

20x-(4(2x-3)+2(x-4))-50+10=0



We calculate terms in parentheses: -(4(2x-3)+2(x-4)), so:

4(2x-3)+2(x-4)

We multiply parentheses

8x+2x-12-8

We add all the numbers together, and all the variables

10x-20

Back to the equation:

-(10x-20)



We add all the numbers together, and all the variables

20x-(10x-20)-40=0

We get rid of parentheses

20x-10x+20-40=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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