5(4x+40)-34(2x-7)=4x(5-9)+87x

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Solution for 5(4x+40)-34(2x-7)=4x(5-9)+87x equation: 



5(4x+40)-34(2x-7)=4x(5-9)+87x

We move all terms to the left:

5(4x+40)-34(2x-7)-(4x(5-9)+87x)=0

We add all the numbers together, and all the variables

5(4x+40)-34(2x-7)-(4x(-4)+87x)=0

We multiply parentheses

20x-68x-(4x(-4)+87x)+200+238=0



We calculate terms in parentheses: -(4x(-4)+87x), so:

4x(-4)+87x

We add all the numbers together, and all the variables

87x+4x(-4)

We multiply parentheses

87x-16x

We add all the numbers together, and all the variables

71x

Back to the equation:

-(71x)



We add all the numbers together, and all the variables

-119x+438=0

We move all terms containing x to the left, all other terms to the right

-119x=-438

x=-438/-119

x=3+81/119

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